Integrand size = 11, antiderivative size = 61 \[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=-\frac {b x}{a^2}-\frac {2 b^2 \text {arctanh}\left (\frac {a+b \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{a^2 \sqrt {a^2-b^2}}-\frac {\cos (x)}{a} \]
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Time = 0.11 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.545, Rules used = {3938, 12, 3868, 2739, 632, 212} \[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=-\frac {2 b^2 \text {arctanh}\left (\frac {a+b \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{a^2 \sqrt {a^2-b^2}}-\frac {b x}{a^2}-\frac {\cos (x)}{a} \]
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Rule 12
Rule 212
Rule 632
Rule 2739
Rule 3868
Rule 3938
Rubi steps \begin{align*} \text {integral}& = -\frac {\cos (x)}{a}-\frac {\int \frac {b}{a+b \csc (x)} \, dx}{a} \\ & = -\frac {\cos (x)}{a}-\frac {b \int \frac {1}{a+b \csc (x)} \, dx}{a} \\ & = -\frac {b x}{a^2}-\frac {\cos (x)}{a}+\frac {b \int \frac {1}{1+\frac {a \sin (x)}{b}} \, dx}{a^2} \\ & = -\frac {b x}{a^2}-\frac {\cos (x)}{a}+\frac {(2 b) \text {Subst}\left (\int \frac {1}{1+\frac {2 a x}{b}+x^2} \, dx,x,\tan \left (\frac {x}{2}\right )\right )}{a^2} \\ & = -\frac {b x}{a^2}-\frac {\cos (x)}{a}-\frac {(4 b) \text {Subst}\left (\int \frac {1}{-4 \left (1-\frac {a^2}{b^2}\right )-x^2} \, dx,x,\frac {2 a}{b}+2 \tan \left (\frac {x}{2}\right )\right )}{a^2} \\ & = -\frac {b x}{a^2}-\frac {2 b^2 \text {arctanh}\left (\frac {b \left (\frac {a}{b}+\tan \left (\frac {x}{2}\right )\right )}{\sqrt {a^2-b^2}}\right )}{a^2 \sqrt {a^2-b^2}}-\frac {\cos (x)}{a} \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.92 \[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=-\frac {b x-\frac {2 b^2 \arctan \left (\frac {a+b \tan \left (\frac {x}{2}\right )}{\sqrt {-a^2+b^2}}\right )}{\sqrt {-a^2+b^2}}+a \cos (x)}{a^2} \]
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Time = 0.46 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.20
method | result | size |
default | \(\frac {2 b^{2} \arctan \left (\frac {2 b \tan \left (\frac {x}{2}\right )+2 a}{2 \sqrt {-a^{2}+b^{2}}}\right )}{a^{2} \sqrt {-a^{2}+b^{2}}}+\frac {-\frac {2 a}{1+\tan \left (\frac {x}{2}\right )^{2}}-2 b \arctan \left (\tan \left (\frac {x}{2}\right )\right )}{a^{2}}\) | \(73\) |
risch | \(-\frac {x b}{a^{2}}-\frac {{\mathrm e}^{i x}}{2 a}-\frac {{\mathrm e}^{-i x}}{2 a}+\frac {i b^{2} \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {-a^{2}+b^{2}}\, b -a^{2}+b^{2}\right )}{a \sqrt {-a^{2}+b^{2}}}\right )}{\sqrt {-a^{2}+b^{2}}\, a^{2}}-\frac {i b^{2} \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {-a^{2}+b^{2}}\, b +a^{2}-b^{2}\right )}{a \sqrt {-a^{2}+b^{2}}}\right )}{\sqrt {-a^{2}+b^{2}}\, a^{2}}\) | \(161\) |
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Time = 0.28 (sec) , antiderivative size = 235, normalized size of antiderivative = 3.85 \[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=\left [\frac {\sqrt {a^{2} - b^{2}} b^{2} \log \left (-\frac {{\left (a^{2} - 2 \, b^{2}\right )} \cos \left (x\right )^{2} + 2 \, a b \sin \left (x\right ) + a^{2} + b^{2} - 2 \, {\left (b \cos \left (x\right ) \sin \left (x\right ) + a \cos \left (x\right )\right )} \sqrt {a^{2} - b^{2}}}{a^{2} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2}}\right ) - 2 \, {\left (a^{2} b - b^{3}\right )} x - 2 \, {\left (a^{3} - a b^{2}\right )} \cos \left (x\right )}{2 \, {\left (a^{4} - a^{2} b^{2}\right )}}, -\frac {\sqrt {-a^{2} + b^{2}} b^{2} \arctan \left (-\frac {\sqrt {-a^{2} + b^{2}} {\left (b \sin \left (x\right ) + a\right )}}{{\left (a^{2} - b^{2}\right )} \cos \left (x\right )}\right ) + {\left (a^{2} b - b^{3}\right )} x + {\left (a^{3} - a b^{2}\right )} \cos \left (x\right )}{a^{4} - a^{2} b^{2}}\right ] \]
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\[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=\int \frac {\sin {\left (x \right )}}{a + b \csc {\left (x \right )}}\, dx \]
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Exception generated. \[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.27 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.26 \[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=\frac {2 \, {\left (\pi \left \lfloor \frac {x}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (b\right ) + \arctan \left (\frac {b \tan \left (\frac {1}{2} \, x\right ) + a}{\sqrt {-a^{2} + b^{2}}}\right )\right )} b^{2}}{\sqrt {-a^{2} + b^{2}} a^{2}} - \frac {b x}{a^{2}} - \frac {2}{{\left (\tan \left (\frac {1}{2} \, x\right )^{2} + 1\right )} a} \]
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Time = 19.00 (sec) , antiderivative size = 766, normalized size of antiderivative = 12.56 \[ \int \frac {\sin (x)}{a+b \csc (x)} \, dx=-\frac {2}{a\,\left ({\mathrm {tan}\left (\frac {x}{2}\right )}^2+1\right )}-\frac {b\,x}{a^2}-\frac {b^2\,\mathrm {atan}\left (\frac {\frac {b^2\,\sqrt {a^2-b^2}\,\left (\frac {32\,b^4}{a}-\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (2\,a\,b^5-2\,a^3\,b^3\right )}{a^3}+\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^2\,b^2+64\,a\,b^3\,\mathrm {tan}\left (\frac {x}{2}\right )+\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^3\,b^2+\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (3\,a^7\,b-2\,a^5\,b^3\right )}{a^3}\right )}{a^4-a^2\,b^2}\right )}{a^4-a^2\,b^2}\right )\,1{}\mathrm {i}}{a^4-a^2\,b^2}-\frac {b^2\,\sqrt {a^2-b^2}\,\left (\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (2\,a\,b^5-2\,a^3\,b^3\right )}{a^3}-\frac {32\,b^4}{a}+\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^2\,b^2+64\,a\,b^3\,\mathrm {tan}\left (\frac {x}{2}\right )-\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^3\,b^2+\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (3\,a^7\,b-2\,a^5\,b^3\right )}{a^3}\right )}{a^4-a^2\,b^2}\right )}{a^4-a^2\,b^2}\right )\,1{}\mathrm {i}}{a^4-a^2\,b^2}}{\frac {128\,b^5\,\mathrm {tan}\left (\frac {x}{2}\right )}{a^3}+\frac {b^2\,\sqrt {a^2-b^2}\,\left (\frac {32\,b^4}{a}-\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (2\,a\,b^5-2\,a^3\,b^3\right )}{a^3}+\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^2\,b^2+64\,a\,b^3\,\mathrm {tan}\left (\frac {x}{2}\right )+\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^3\,b^2+\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (3\,a^7\,b-2\,a^5\,b^3\right )}{a^3}\right )}{a^4-a^2\,b^2}\right )}{a^4-a^2\,b^2}\right )}{a^4-a^2\,b^2}+\frac {b^2\,\sqrt {a^2-b^2}\,\left (\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (2\,a\,b^5-2\,a^3\,b^3\right )}{a^3}-\frac {32\,b^4}{a}+\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^2\,b^2+64\,a\,b^3\,\mathrm {tan}\left (\frac {x}{2}\right )-\frac {b^2\,\sqrt {a^2-b^2}\,\left (32\,a^3\,b^2+\frac {32\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (3\,a^7\,b-2\,a^5\,b^3\right )}{a^3}\right )}{a^4-a^2\,b^2}\right )}{a^4-a^2\,b^2}\right )}{a^4-a^2\,b^2}}\right )\,\sqrt {a^2-b^2}\,2{}\mathrm {i}}{a^4-a^2\,b^2} \]
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